Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 08:21Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-t²) dt = √π / 2
75K
CH₄ + 2O₂ → CO₂ + 2H₂O
479K
11n² + 1n + 0 = 0
det| 10 7 ; 3 11 | = 89
129K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
∑_{k=1}^{n} k = n(n+1)/2
191K
det| 7 4 ; 4 8 | = 40
390K
4y² + 8y + 1 = 0
det| 11 7 ; 4 12 | = 104
∑_{k=1}^{n} k = n(n+1)/2
473K