Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 07:46Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
326K
det| 5 6 ; 2 6 | = 18
198K
7r² + 8r + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
det| 10 9 ; 3 11 | = 83
2ψ² + 6ψ + 0 = 0
det| 2 5 ; 6 3 | = -24
ω = 2πf
∂ψ/∂t = 3ψ