Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 15:22Z
\lim_{y\to 0} \frac{\sin y}{y} = 1
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∫₀^∞ e^(-φ²) dφ = √π / 2
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det| 8 8 ; 0 9 | = 72
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
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AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 5 9 ; 0 6 | = 30
263K