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Math Dump /sym/7fd97a

id=1 · host=jp.commstar.world · 2026-10-19 04:36Z

E = mc²
rxn_1394.tex
1α² + 9α + 4 = 0
326K
ops_1628.mol
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
198K
det| 10 7 ; 4 11 | = 82
eq_9015.json
\oint_C \vec{F}\cdot d\vec{r} = 0
155K
eq_1210.eqn
det| 3 6 ; 0 4 | = 12
63K
λ = h/p
spec_6726.json
E = mc²
366K
spec_6630.dat
det| 7 4 ; 4 8 | = 40
201K
4θ² + 9θ + 6 = 0
ops_0548.json
\binom{n}{k} = \frac{n!}{k!(n-k)!}
176K
mat_6103.dat
N₂ + 3H₂ ⇌ 2NH₃
319K
det| 8 5 ; 5 9 | = 47
ops_6587.eqn
∇ × E = −∂B/∂t
359K
spec_4768.mol
∑_{k=1}^{n} k = n(n+1)/2
263K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
d/dx [x^12] = 12x^11
3n² + 5n + 4 = 0
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