Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 05:52Z
det| 3 3 ; 5 4 | = -3
det| 7 4 ; 4 8 | = 40
75K
∇²β = 0
e^{i\pi} + 1 = 0
∫₀^∞ e^(-x²) dx = √π / 2
390K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
1K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 3 7 ; 2 4 | = -2
∫₀^∞ e^(-φ²) dφ = √π / 2
188K
∑_{k=1}^{n} k = n(n+1)/2
416K
∂t/∂β = 2t