Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 05:00Z
∑_{k=1}^{n} k = n(n+1)/2
det| 3 6 ; 0 4 | = 12
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11y² + 4y + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
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d/dy [y^6] = 6y^5
det| 9 4 ; 1 10 | = 86
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8ω² + 6ω + 2 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
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∑_{k=1}^{n} k = n(n+1)/2
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det| 7 6 ; 1 8 | = 50
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