Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 07:53Z
ω = 2πf
7r² + 8r + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
63K
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-x²) dx = √π / 2
366K
det| 6 6 ; 3 7 | = 24
201K
det| 10 9 ; 3 11 | = 83
2ψ² + 6ψ + 0 = 0
ω = 2πf
∂ψ/∂t = 3ψ
6θ² + 3θ + 6 = 0
det| 8 4 ; 5 9 | = 52