Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:56Z
∑_{k=1}^{n} k = n(n+1)/2
det| 7 9 ; 1 8 | = 47
479K
3β² + 6β + 2 = 0
det| 10 9 ; 0 11 | = 110
129K
F = ma
∑_{k=1}^{n} k = n(n+1)/2
191K
det| 9 4 ; 1 10 | = 86
390K
det| 12 1 ; 4 13 | = 152
1K
∑_{k=1}^{n} k = n(n+1)/2
153K