Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 13:03Z
2α² + 5α + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
479K
iħ ∂ψ/∂t = Ĥψ
9φ² + 5φ + 2 = 0
d/dω [ω^2] = 2ω^1
det| 9 4 ; 1 10 | = 86
1K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
473K
∑_{k=1}^{n} k = n(n+1)/2
338K