Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:13Z
∑_{k=1}^{n} k = n(n+1)/2
det| 5 3 ; 7 6 | = 9
479K
3β² + 6β + 2 = 0
F = ma
det| 9 4 ; 1 10 | = 86
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\frac{8}{7} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
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Fe₂O₃ + 3CO → 2Fe + 3CO₂
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∫₀^∞ e^(-t²) dt = √π / 2
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∑_{k=1}^{n} k = n(n+1)/2
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det| 3 7 ; 2 4 | = -2
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