Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:34Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
det| 7 4 ; 4 8 | = 40
276K
det| 4 6 ; 4 5 | = -4
129K
F = ma
det| 5 6 ; 2 6 | = 18
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\frac{8}{7} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-φ²) dφ = √π / 2
153K
∫₀^∞ e^(-ψ²) dψ = √π / 2
473K