Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:34Z
11t² + 7t + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
326K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
198K
E = mc²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
63K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 7 4 ; 4 8 | = 40
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 4 4 ; 5 5 | = 0
176K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∑_{k=1}^{n} k = n(n+1)/2
233K