Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:59Z
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
479K
8β² + 2β + 0 = 0
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
129K
∑_{k=1}^{n} k = n(n+1)/2
det| 7 4 ; 4 8 | = 40
390K
\lim_{r\to 0} \frac{\sin r}{r} = 1
\binom{n}{k} = \frac{n!}{k!(n-k)!}
1K
det| 12 1 ; 1 13 | = 155
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-θ²) dθ = √π / 2
det| 5 5 ; 2 6 | = 20