Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:26Z
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
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\frac{8}{9} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
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F = ma
det| 9 4 ; 1 10 | = 86
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det| 12 1 ; 4 13 | = 152
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∑_{k=1}^{n} k = n(n+1)/2
153K
det| 3 7 ; 2 4 | = -2
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