Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:27Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
75K
det| 11 9 ; 5 12 | = 87
479K
3β² + 6β + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
276K
det| 10 7 ; 3 11 | = 89
129K
F = ma
det| 7 4 ; 4 8 | = 40
390K
det| 10 9 ; 0 11 | = 110
473K