Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 21:46Z
d/dx [x^11] = 11x^10
det| 5 9 ; 7 6 | = -33
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
278K
4r² + 1r + 1 = 0
∫₀^∞ e^(-x²) dx = √π / 2
392K
∫₀^∞ e^(-φ²) dφ = √π / 2
233K
∂φ/∂θ = 6φ
det| 9 4 ; 1 10 | = 86
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∑_{k=1}^{n} k = n(n+1)/2
330K
det| 2 1 ; 7 3 | = -1
\frac{10}{1} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O