Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 23:09Z
d/dα [α^11] = 11α^10
∑_{k=1}^{n} k = n(n+1)/2
234K
\frac{3}{5} \sum_{i=1}^{n} i^{2}
det| 10 9 ; 0 11 | = 110
392K
det| 11 9 ; 0 12 | = 132
233K
λ = h/p
det| 1 4 ; 3 2 | = -10
330K
10r² + 3r + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
223K
det| 9 4 ; 1 10 | = 86
28K