Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:01Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
det| 11 4 ; 5 12 | = 112
276K
∑_{k=1}^{n} k = n(n+1)/2
129K
F = ma
∑_{k=1}^{n} k = n(n+1)/2
153K
det| 10 4 ; 1 11 | = 106
473K
det| 9 4 ; 1 10 | = 86
338K