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Math Dump /sym/7fd97a

id=1 · host=jp.commstar.world · 2026-10-19 04:25Z

E = mc²
eq_4588.dat
8ψ² + 7ψ + 0 = 0
326K
eq_9442.mol
e^{i\pi} + 1 = 0
198K
det| 10 7 ; 4 11 | = 82
ops_1628.mol
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
155K
mat_1689.dat
det| 6 6 ; 3 7 | = 24
63K
λ = h/p
eq_9312.eqn
ΔS ≥ 0
366K
ops_1696.eqn
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
201K
4θ² + 9θ + 6 = 0
ops_5618.csv
∇ × E = −∂B/∂t
176K
ops_2883.eqn
\lim_{t\to 0} \frac{\sin t}{t} = 1
319K
det| 8 5 ; 5 9 | = 47
spec_7724.csv
d/dt [t^3] = 3t^2
359K
\frac{1}{9} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
d/dx [x^12] = 12x^11
3n² + 5n + 4 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
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