Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:16Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
det| 3 6 ; 0 4 | = 12
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∑_{k=1}^{n} k = n(n+1)/2
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F = ma
\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 3 3 ; 4 4 | = 0
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1x² + 5x + 7 = 0
det| 5 6 ; 7 6 | = -12
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det| 11 4 ; 5 12 | = 112
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∇²ψ = 0