Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 02:27Z
det| 2 2 ; 6 3 | = -6
∫₀^∞ e^(-t²) dt = √π / 2
326K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
det| 3 1 ; 4 4 | = 8
det| 7 6 ; 1 8 | = 50
366K
det| 11 9 ; 5 12 | = 87
201K
ΔS ≥ 0
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
10φ² + 7φ + 2 = 0