Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:11Z
11t² + 7t + 4 = 0
E = mc²
Fe₂O₃ + 3CO → 2Fe + 3CO₂
155K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{t\to 0} \frac{\sin t}{t} = 1
366K
∫₀^∞ e^(-t²) dt = √π / 2
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
∫₀^∞ e^(-φ²) dφ = √π / 2
176K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
319K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
ΔS ≥ 0
det| 10 1 ; 4 11 | = 106
e^{i\pi} + 1 = 0