Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:08Z
11t² + 7t + 4 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
326K
E = mc²
det| 10 2 ; 1 11 | = 108
155K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 5 2 ; 3 6 | = 24
366K
CH₄ + 2O₂ → CO₂ + 2H₂O
Fe₂O₃ + 3CO → 2Fe + 3CO₂
176K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 10 1 ; 4 11 | = 106
∫₀^∞ e^(-t²) dt = √π / 2
233K
∑_{k=1}^{n} k = n(n+1)/2
412K
∑_{k=1}^{n} k = n(n+1)/2
iħ ∂ψ/∂t = Ĥψ