Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:43Z
11t² + 7t + 4 = 0
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
155K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 7 6 ; 1 8 | = 50
366K
CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
319K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
d/dy [y^11] = 11y^10
233K
det| 7 4 ; 4 8 | = 40
412K