Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 16:47Z
7φ² + 4φ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
326K
E = mc²
det| 4 6 ; 4 5 | = -4
155K
det| 7 4 ; 4 8 | = 40
63K
e^{i\pi} + 1 = 0
det| 5 2 ; 3 6 | = 24
366K
det| 5 9 ; 7 6 | = -33
201K
∑_{k=1}^{n} k = n(n+1)/2
319K