Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:43Z
∇²α = 0
∑_{k=1}^{n} k = n(n+1)/2
326K
det| 7 4 ; 4 8 | = 40
198K
6φ² + 8φ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
63K
∂φ/∂φ = 1φ
det| 4 8 ; 1 5 | = 12
CH₄ + 2O₂ → CO₂ + 2H₂O
176K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
∑_{k=1}^{n} k = n(n+1)/2
359K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O