Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:28Z
∇ × E = −∂B/∂t
\frac{8}{9} \sum_{i=1}^{n} i^{2}
F = ma
\binom{n}{k} = \frac{n!}{k!(n-k)!}
390K
10n² + 4n + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
153K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-γ²) dγ = √π / 2
\binom{n}{k} = \frac{n!}{k!(n-k)!}
188K
∂ω/∂z = 1ω