Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:18Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
det| 5 9 ; 0 6 | = 30
129K
F = ma
det| 1 4 ; 3 2 | = -10
191K
∫₀^∞ e^(-x²) dx = √π / 2
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
1K