Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:02Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
F = ma
\binom{n}{k} = \frac{n!}{k!(n-k)!}
191K
det| 8 9 ; 4 9 | = 36
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\frac{8}{7} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
1K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
153K
1x² + 5x + 7 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
338K
d/dy [y^11] = 11y^10
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