Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:51Z
2ψ² + 5ψ + 4 = 0
N₂ + 3H₂ ⇌ 2NH₃
det| 5 6 ; 2 6 | = 18
276K
∫₀^∞ e^(-n²) dn = √π / 2
129K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
CH₄ + 2O₂ → CO₂ + 2H₂O
191K
det| 7 4 ; 4 8 | = 40
390K
∇²z = 0
∑_{k=1}^{n} k = n(n+1)/2
153K
N₂ + 3H₂ ⇌ 2NH₃
8t² + 2t + 3 = 0
det| 1 1 ; 5 2 | = -3
188K
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
F = ma
∫₀^∞ e^(-φ²) dφ = √π / 2