Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:09Z
11t² + 7t + 4 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
198K
E = mc²
det| 10 2 ; 1 11 | = 108
155K
∑_{k=1}^{n} k = n(n+1)/2
63K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 3 1 ; 7 4 | = 5
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
AgNO₃ + NaCl → AgCl↓ + NaNO₃
Fe₂O₃ + 3CO → 2Fe + 3CO₂
359K
det| 10 1 ; 4 11 | = 106
det| 1 4 ; 3 2 | = -10
233K
∑_{k=1}^{n} k = n(n+1)/2
412K
∑_{k=1}^{n} k = n(n+1)/2