Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:04Z
11t² + 7t + 4 = 0
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 7 4 ; 4 8 | = 40
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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CH₄ + 2O₂ → CO₂ + 2H₂O
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∑_{k=1}^{n} k = n(n+1)/2
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det| 10 1 ; 4 11 | = 106
det| 4 4 ; 5 5 | = 0
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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