Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 14:47Z
∫₀^∞ e^(-ψ²) dψ = √π / 2
det| 1 4 ; 3 2 | = -10
479K
e^{i\pi} + 1 = 0
det| 9 4 ; 1 10 | = 86
276K
2H₂ + O₂ → 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
1K
\oint_C \vec{F}\cdot d\vec{r} = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
338K
∫₀^∞ e^(-β²) dβ = √π / 2
∫₀^∞ e^(-t²) dt = √π / 2