Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:40Z
2ψ² + 5ψ + 4 = 0
N₂ + 3H₂ ⇌ 2NH₃
det| 4 8 ; 3 5 | = -4
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\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∇²z = 0
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-x²) dx = √π / 2
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O