Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:42Z
2ψ² + 5ψ + 4 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
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\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∇²z = 0
N₂ + 3H₂ ⇌ 2NH₃
det| 4 4 ; 5 5 | = 0
473K
8t² + 2t + 3 = 0
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
F = ma
∫₀^∞ e^(-φ²) dφ = √π / 2