Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:59Z
∑_{k=1}^{n} k = n(n+1)/2
8β² + 2β + 0 = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
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∑_{k=1}^{n} k = n(n+1)/2
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 5 6 ; 7 6 | = -12
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∑_{k=1}^{n} k = n(n+1)/2
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