Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:37Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
479K
3β² + 6β + 2 = 0
det| 5 9 ; 0 6 | = 30
276K
F = ma
Fe₂O₃ + 3CO → 2Fe + 3CO₂
191K
∑_{k=1}^{n} k = n(n+1)/2
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
1x² + 5x + 7 = 0