Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:27Z
∇²α = 0
6φ² + 8φ + 4 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
155K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
63K
∂φ/∂φ = 1φ
CH₄ + 2O₂ → CO₂ + 2H₂O
366K
∫₀^∞ e^(-φ²) dφ = √π / 2
201K
det| 4 8 ; 1 5 | = 12
CH₄ + 2O₂ → CO₂ + 2H₂O
176K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
319K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
7φ² + 2φ + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∇²r = 0