Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:35Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
276K
F = ma
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
153K
1x² + 5x + 7 = 0
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
338K