Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:21Z
11t² + 7t + 4 = 0
E = mc²
det| 10 4 ; 1 11 | = 106
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∑_{k=1}^{n} k = n(n+1)/2
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
CH₄ + 2O₂ → CO₂ + 2H₂O
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 10 1 ; 4 11 | = 106
det| 7 2 ; 3 8 | = 50
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∑_{k=1}^{n} k = n(n+1)/2
iħ ∂ψ/∂t = Ĥψ