Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 05:46Z
det| 3 3 ; 5 4 | = -3
det| 7 4 ; 4 8 | = 40
75K
det| 4 6 ; 4 5 | = -4
479K
∇²β = 0
e^{i\pi} + 1 = 0
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
1K
det| 1 4 ; 0 2 | = 2
153K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 5 2 ; 3 6 | = 24
473K
det| 3 7 ; 2 4 | = -2
∫₀^∞ e^(-n²) dn = √π / 2
188K
det| 4 8 ; 3 5 | = -4
416K
∂t/∂β = 2t
PV = nRT