Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 16:35Z
7φ² + 4φ + 5 = 0
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
155K
∑_{k=1}^{n} k = n(n+1)/2
63K
e^{i\pi} + 1 = 0
det| 3 1 ; 7 4 | = 5
366K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 9 4 ; 1 10 | = 86
319K
d/dβ [β^2] = 2β^1
∑_{k=1}^{n} k = n(n+1)/2
359K