Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:37Z
∇²α = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
326K
6φ² + 8φ + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
155K
∂φ/∂φ = 1φ
∑_{k=1}^{n} k = n(n+1)/2
201K
det| 4 8 ; 1 5 | = 12
det| 7 4 ; 4 8 | = 40
176K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
319K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
det| 5 3 ; 7 6 | = 9
359K
∑_{k=1}^{n} k = n(n+1)/2
263K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∇²r = 0
det| 12 9 ; 2 13 | = 138
\frac{8}{5} \sum_{i=1}^{n} i^{2}