Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:16Z
11t² + 7t + 4 = 0
E = mc²
∫₀^∞ e^(-x²) dx = √π / 2
155K
\frac{2}{2} \sum_{i=1}^{n} i^{2}
63K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 1 4 ; 3 2 | = -10
319K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
ΔS ≥ 0
det| 10 1 ; 4 11 | = 106
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2