Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 00:37Z
12r² + 5r + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
326K
iħ ∂ψ/∂t = Ĥψ
det| 7 4 ; 4 8 | = 40
155K
11x² + 6x + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
366K
det| 10 7 ; 3 11 | = 89
201K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
176K
∫₀^∞ e^(-φ²) dφ = √π / 2
319K
∫₀^∞ e^(-ψ²) dψ = √π / 2
359K
CH₄ + 2O₂ → CO₂ + 2H₂O
263K