Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:36Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-z²) dz = √π / 2
479K
3β² + 6β + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
129K
F = ma
\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 9 4 ; 1 10 | = 86
153K
det| 1 1 ; 5 2 | = -3
473K
∫₀^∞ e^(-t²) dt = √π / 2
416K