Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 02:57Z
det| 2 2 ; 6 3 | = -6
∑_{k=1}^{n} k = n(n+1)/2
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Fe₂O₃ + 3CO → 2Fe + 3CO₂
∫₀^∞ e^(-φ²) dφ = √π / 2
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det| 3 1 ; 4 4 | = 8
∑_{k=1}^{n} k = n(n+1)/2
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det| 7 4 ; 4 8 | = 40
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ΔS ≥ 0
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
10φ² + 7φ + 2 = 0