Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:18Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
det| 7 4 ; 4 8 | = 40
276K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
129K
F = ma
∑_{k=1}^{n} k = n(n+1)/2
191K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
CH₄ + 2O₂ → CO₂ + 2H₂O
153K
∫₀^∞ e^(-ψ²) dψ = √π / 2
473K
∑_{k=1}^{n} k = n(n+1)/2
338K