Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:32Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
det| 7 2 ; 7 8 | = 42
129K
F = ma
∑_{k=1}^{n} k = n(n+1)/2
191K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
1K
∑_{k=1}^{n} k = n(n+1)/2
153K
det| 7 6 ; 1 8 | = 50
473K
det| 7 4 ; 4 8 | = 40
188K