Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:25Z
11t² + 7t + 4 = 0
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-n²) dn = √π / 2
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
CH₄ + 2O₂ → CO₂ + 2H₂O
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AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 4 4 ; 5 5 | = 0
359K
det| 10 1 ; 4 11 | = 106
det| 3 6 ; 0 4 | = 12
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
412K
∑_{k=1}^{n} k = n(n+1)/2